There are two beakers:

I. Beaker with pure volatile solvent
II. Beaker with volatile solvent and non-volatile solute

If both beakers are placed together in a closed container, then:

A. Volume of the solvent beaker will decrease and the solution beaker will increase
B. Volume of the solvent beaker will increase and the solution beaker will also increase
C. Volume of the solvent beaker will decrease and the solution beaker will also decrease
D. Volume of the solvent beaker will increase and the solution beaker will decrease

The volume of the solvent in beaker I will decrease while the volume of the solution in beaker II will increase, due to the non-volatile solute lowering the vapor pressure of the solution.

Explanation:

When two beakers are placed in a closed container, one with pure volatile solvent and the other with the same volatile solvent but containing a non-volatile solute, a dynamic equilibrium of evaporation and condensation will occur. Due to the presence of the non-volatile solute, the vapor pressure of the solution in beaker II is lower than that of the pure solvent in beaker I. As a result, the solvent in beaker I will have a higher tendency to evaporate and, once vaporized, condense into the beaker with the solution. Therefore, there will be a net transfer of solvent molecules from beaker I to beaker II. Consequently, the volume of the solvent in beaker I will decrease, while the volume of the solution in beaker II will increase. This process continues until all the solvent evaporates from beaker I and condenses into beaker II, or until an equilibrium is reached where the rates of evaporation and condensation are equal.