Answer :
Final answer:
The formula q=mc∆T can be used to calculate the final temperature of the water after 37.1 kJ of heat has been absorbed. Plugging in the numbers, we find that the final temperature will be 98.9 °C.
Explanation:
In order to find the final temperature of the water after 37.1 kJ of heat is absorbed, we need to use the formula q=mc∆T, where 'q' is the heat absorbed, 'm' is the mass of the water, 'c' is the specific heat capacity of water, and '∆T' is the change in temperature. First, we need to convert the volume of the water to mass, given that the density of water is approximately 1 g/mL, the mass of 125 mL of water is 125 grams. Now, we can plug the values into the formula: 37,100 J = 125g * 4.184 J/g°C * ∆T. Solving for ∆T, we find that it is approximately 70.9 °C. Therefore, the final temperature of the water will be 70.9 °C + initial temperature 28.0 °C, which equates to 98.9 °C.
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