A ball is dropped off the side of a bridge. After falling for 1.55 seconds, how far has it fallen? (Assuming [tex]g = -9.8 \, \text{m/s}^2[/tex])

A) 11.9 m
B) 18.1 m
C) 22.7 m
D) 27.2 m

The ball has fallen approximately 11.8 meters after 1.55 seconds of drop time, using the kinematic equation for displacement in free fall. The correct answer is option A) 11.9 m.

Explanation:

To determine how far the ball has fallen after 1.55 seconds, we can use the equation for the displacement 's' of an object in free fall with an initial velocity of zero, which is given by s = 0.5 * g * t2, where 'g' is the acceleration due to gravity (9.8 m/s2) and 't' is the time in seconds.

Plugging in the values, we get

s = 0.5 * 9.8 m/s2 * (1.55 s)2

= 11.8 m (rounded to one decimal place).

A ball is dropped off the side of a bridge. After falling for 1.55 seconds, how far has it fallen? (Assuming [tex]g = -9.8 \, \text{m/s}^2[/tex])A) 11.9 m B) 18.1 m C) 22.7 m D) 27.2 m

Answer :

Final answer:

Explanation:

Other Questions

A ball is dropped off the side of a bridge. After falling for 1.55 seconds, how far has it fallen? (Assuming [tex]g = -9.8 \, \text{m/s}^2[/tex])

A) 11.9 m
B) 18.1 m
C) 22.7 m
D) 27.2 m