A 92-kg rugby player running at 7.5 m/s collides in midair with a 112-kg player moving in the opposite direction. After the collision, each player has zero velocity.

What was the initial speed of the 112-kg player before the collision?

To solve this problem, we can use the principle of conservation of momentum. Before the collision, the total momentum of the system is zero since both players are moving in opposite directions. After the collision, when both players have zero velocity, the total momentum is also zero.

We can use the formula for momentum, which is calculated by multiplying mass and velocity:

Momentum = mass x velocity

Using this formula, we can set up the following equation:

(92 kg) x (7.5 m/s) + (112 kg) x (v) = 0, where v is the initial velocity of the 112-kg player.

Solving for v, we find that the initial speed of the 112-kg player before the collision was -6.6 m/s.

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A 92-kg rugby player running at 7.5 m/s collides in midair with a 112-kg player moving in the opposite direction. After the collision, each player has zero velocity.What was the initial speed of the 112-kg player before the collision?

Answer :

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A 92-kg rugby player running at 7.5 m/s collides in midair with a 112-kg player moving in the opposite direction. After the collision, each player has zero velocity.

What was the initial speed of the 112-kg player before the collision?