College

The number of bacteria in a petri dish is doubling every 38.4 minutes. Currently, the petri dish contains 562 bacteria. In how many minutes will the petri dish contain 10,000 bacteria?

Answer :

The time in minutes when the petri dish contain 10,000 bacteria is 159.36 minutes.

What is defined as the rate of increase?

  • The momentum of a variable is represented by the rate of change, which is used to mathematically define the percentage change in value above a defined period of time.
  • The rate of change equation describes the relationship between how each quantity shifts in relation to how another quantity changes.

For the given question;

The time of doubling of number of bacteria in a petri dish = 38.4 minutes.

Present number of bacteria = 562.

Final number of bacteria = 10,000.

Let the 'x' be the current number of bacteria.

Let 'n' be the time of doubling.

Then,

2ⁿx = Final bacteria

Put the values;

2ⁿ×562 = 10, 000

2ⁿ = 10,000/562

2ⁿ = 17.79

Taking natural log both side;

㏑2ⁿ = ㏑17.79

Using the power law of log.

n ㏑2 = ㏑17.79

n = ㏑17.79/㏑2

Solve using calculator;

n = 4.15

The doubling rate was every 38.4 minutes.

Thus, for n = 4.15.

Thus, time = 4.15× 38.4 minutes.

Time = 159.36 minutes.

Therefore, the time after which the number of bacteria in the petri dish will be 10,000 is 159.36 minutes.

To know more about the rate of change, here

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Final answer:

Using the exponential growth formula, we calculated that it would take approximately 114.57 minutes for the bacteria to grow from 562 to 10,000 in a petri dish with a doubling time of 38.4 minutes.

Explanation:

To determine the number of minutes it will take for the number of bacteria to increase from 562 to 10,000 with a doubling time of every 38.4 minutes, we can use the formula for exponential growth:

N = N_0 × 2^(t/T)

where N is the final number of bacteria, N_0 is the initial number of bacteria, t is the total time in minutes, and T is the doubling time in minutes.

First, let's isolate t in the formula:

t = T × (log(N/N_0) / log(2))

We know that N = 10,000, N_0 = 562, and T = 38.4 minutes. Plugging these values into the formula, we obtain:

t = 38.4 × (log(10,000/562) / log(2))

After performing the calculations, we find that t is approximately 114.57 minutes. Therefore, it will take roughly 114.57 minutes for the number of bacteria to grow from 562 to 10,000.