Answer :
Final answer:
The energy absorbed by a 9.5 kg outdoor copper sculpture, when heated from 24°C to 78°C, is calculated using the formula for heat (Q = m * c * ΔT), where m is the mass, c is specific heat, and ΔT is the change in temperature. The result after substituting corresponding values is 199,215 J.
Explanation:
The question pertains to the concept of specific heat, which indicates the amount of heat per unit mass required to raise the temperature by one degree Celsius. In this case, we have a 9.5 kg copper sculpture whose temperature raises from 24°C to 78°C. The specific heat of copper is 0.390 J/g °C. To find the energy absorbed, we need to use the formula Q=m*c*ΔT, where Q is the heat absorbed, m is the mass, c is the specific heat, and ΔT is the change in temperature.
Converting mass from kilogram to grams (1 kg = 1000 g), the mass of the sculpture is 9500 g. The change in temperature (ΔT) is 78°C - 24°C = 54°C.
Substituting these values to our formula: Q = 9500 g * 0.390 J/g °C * 54°C = 199215 Joule. Therefore, option (a) is the answer, and the absorbed energy is 199,215 J.
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