High School

A 82 kg block is pulled at a constant speed of 8.5 m/s across a horizontal floor by an applied force of 124 N directed 20° above the horizontal.

What is the rate at which the force does work on the block?

Answer :

The rate at which the force does work on the block is 360 W. Note that since W is the product of force and velocity, the unit of work is joules/second or watts.

We need to find the rate at which the force does work on the block, which can be calculated by the dot product of force and velocity. Let's start with the given data.Weight of the block = 82 kgApplied force = 124 NAngle between the applied force and the horizontal = 20°Speed of the block = 8.5 m/sThe angle between the force and velocity vectors is 20° - 90° = 70°.

Now, let's calculate the rate at which the force does work on the block using the formula W = Fvcosθ, where W is work done, F is force, v is velocity, and θ is the angle between force and velocity. W = 124 N × 8.5 m/s × cos 70°W = 124 N × 8.5 m/s × 0.342W = 359.86 J/s ≈ 360 WTherefore, the rate at which the force does work on the block is 360 W. Note that since W is the product of force and velocity, the unit of work is joules/second or watts.

Learn more about angle here,

https://brainly.com/question/1309590

#SPJ11