Answer :
Final answer:
Using the formula for kinetic energy, (1/2)mv², we find that the trapeze artist with a mass of 64 kg and a velocity of 1.6 m/s has a kinetic energy of approximately 81.92 J, which rounds to 82 J.
Explanation:
The trapeze artist's kinetic energy can be calculated using the formula for kinetic energy: KE = (1/2)mv², where 'm' is the mass of the artist and 'v' is her velocity.
For a trapeze artist with a mass of 64 kg flying at 1.6 m/s, we can plug in these values to get:
KE = (1/2) × 64 kg × (1.6 m/s)²
KE = (0.5) × 64 kg × 2.56 m²/s²
KE = 32 kg × 2.56 m²/s²
KE = 81.92 J
Therefore, the closest answer would be:
C. 82 J
