Answer :
The acceleration of the wakeboarder is equal to 2 m/s².
Describe acceleration.
A body's acceleration can be defined as a change in velocity with respect to time. A vector parameter with both magnitude and direction is acceleration. The first derivative of an object's velocity w.r.t. time and the second derivative of its position with respect to time are used to explain the acceleration.
The force acting is determined by Newton's second law of motion, which states that mass times acceleration equals force (F) (a).
a = F/m and F = ma or
As a result, mass and acceleration (a) are negatively related (m).
Given that the wakeboarder was pushed by the boat with a force of F = 124 N
The wakeboarder weighs 62 kg.
The acceleration of the wakeboarder, a = 124/62 = 2 m/s²
Therefore, the acceleration of the wakeboarder is 2 m/s².
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