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A 4.00 kg ball is moving at 2.00 m/s to the west, and a 6.00 kg ball is moving at 2.00 m/s to the north. What is the total momentum of the system?

Answer :

4.00 kg ball is moving at 2.00 m/s to the West and a 6.00 kg ball is moving at 2.00 m/s to the North. The total momentum of the system is 12.00 kg·m/s upwards.

The total momentum of the system is calculated by adding the momentum of the two objects. The formula for momentum is given by:

momentum = mass × velocity

The momentum of the 4.00 kg ball moving at 2.00 m/s to the west is given by:

momentum = mass × velocity

momentum = 4.00 kg × (-2.00 m/s)momentum = -8.00 kg·m/s (to the left)

The momentum of the 6.00 kg ball moving at 2.00 m/s to the north is given by:

momentum = mass × velocity

momentum = 6.00 kg × 2.00 m/s

momentum = 12.00 kg·m/s (upwards)

The total momentum of the system is the vector sum of the two momenta. The momentum in the vertical direction is 12.00 kg·m/s upwards and there is no momentum in the horizontal direction. Therefore, the total momentum of the system is 12.00 kg·m/s upwards.

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