High School

A 254 kg crate is sitting on level ground. If the static coefficient of friction between the crate and the ground is [tex]u_s = 0.450[/tex], how much force must be applied to start the crate moving?

a) 1120 N
b) 114 N
c) 564 N
d) 5532 N
e) 254 N

Answer :

To start the crate moving on level ground with a static coefficient of friction of 0.450, a force of approximately 1120 N needs to be applied.

The answer is option A

The force required to start the crate moving:

Calculate the normal force: N = mg = (254 kg)(9.8 m/s²) = 2489.2 N

Calculate the maximum static friction force: fs(max) = μs N = (0.450)(2489.2 N) = 1120.64 N

The force needed to start the crate moving is approximately 1120 N.

The answer is option A

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