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------------------------------------------------ A 25.0 L gas cylinder contains a gas at 35.5 atm and

22.8C.

How many moles of gas are in the cylinder?

To find the number of moles of gas in the cylinder, use the ideal gas law equation: PV = nRT. After converting the temperature to Kelvin and substituting all the given values into the formula, we find that the cylinder contains approximately 36 moles of gas.

Explanation:

To find out the number of moles of gas in the cylinder, we can utilize the ideal gas law equation:

PV = nRT,

where P = pressure, V = volume, n = number of moles, R = ideal gas constant and T = temperature in kelvins.

Here, P = 35.5 atm, V = 25.0 L, R = 0.0821 (atm.L/mol.K), and T = 22.8 degrees Celsius.

However, the temperature must be converted into kelvin by adding 273.15. Hence, T = 22.8 C + 273.15 = 296 K.

Inputting these into the ideal gas law equation gives us:

35.5 atm × 25.0 L = n × 0.0821 atm.L/mol.K × 296 K.

Now, isolating n (number of moles), we get:

n = (35.5 atm × 25.0 L) / (0.0821 atm.L/mol.K × 296 K).

After calculating, we find that the number of moles of the gas contained in the cylinder is approximately 36 moles.

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