High School

A 25.0 L gas cylinder contains a gas at 35.5 atm and

22.8C.

How many moles of gas are in the cylinder?

Answer :

Final answer:

To find the number of moles of gas in the cylinder, use the ideal gas law equation: PV = nRT. After converting the temperature to Kelvin and substituting all the given values into the formula, we find that the cylinder contains approximately 36 moles of gas.

Explanation:

To find out the number of moles of gas in the cylinder, we can utilize the ideal gas law equation:

PV = nRT,

where P = pressure, V = volume, n = number of moles, R = ideal gas constant and T = temperature in kelvins.

Here, P = 35.5 atm, V = 25.0 L, R = 0.0821 (atm.L/mol.K), and T = 22.8 degrees Celsius.

However, the temperature must be converted into kelvin by adding 273.15. Hence, T = 22.8 C + 273.15 = 296 K.

Inputting these into the ideal gas law equation gives us:

35.5 atm × 25.0 L = n × 0.0821 atm.L/mol.K × 296 K.

Now, isolating n (number of moles), we get:

n = (35.5 atm × 25.0 L) / (0.0821 atm.L/mol.K × 296 K).

After calculating, we find that the number of moles of the gas contained in the cylinder is approximately 36 moles.

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