Answer :
Final answer:
Using Newton's Second Law of motion and the formula for friction force, the acceleration of the crate is found to be approximately 0.976 m/s², which is not listed among the provided options.
Explanation:
The subject of your question involves the physics concept of Newton's Second Law of Motion and the friction force. If a 235 kg crate is pushed horizontally with a force of 690 N and the coefficient of friction is 0.20, the acceleration of the crate can be calculated.
Let's break it down into steps: first, we calculate the force of friction using the equation:
Force of Friction = Coefficient of Friction * mass * gravity.
Upon substituting the given values, we get Force of Friction = 0.2 * 235 kg * 9.8 m/s2 = 460.6 N
So, the net force F_net = 690 N - 460.6 N = 229.4 N. Finally, substituting these values into Newton's second law equation: a = F/m = 229.4 N / 235 kg = 0.976 m/s2.
Thus, none of the given options a) 3.0 m/s2 b) 3.5 m/s2 c) 4.0 m/s2 d) 4.5 m/s2 is correct. The acceleration of the crate is approximately 0.976 m/s2.
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