A 225 mL gas syringe was at a pressure of 99.3 kPa at 15.0 °C. On the following day, the temperature increased to 25.9 °C, and the new volume was 221.2 mL. What was the atmospheric pressure on this day?

A. 100.2 kPa
B. 101.5 kPa
C. 98.7 kPa
D. 99.9 kPa

To determine the atmospheric pressure on the day the temperature increased to 25.9 °C and the new volume was 221.2 mL, we can use the combined gas law formula: P1V1 / T1 = P2V2 / T2.

First, convert the temperature to Kelvin: T1 = 15.0 °C + 273.15 = 288.15 K, and T2 = 25.9 °C + 273.15 = 299.05 K.

Now, substitute the values into the formula:

P1 * 225 mL / 288.15 K = P2 * 221.2 mL / 299.05 K.

Solving for P2, the atmospheric pressure on this day is approximately 101.5 kPa.

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A 225 mL gas syringe was at a pressure of 99.3 kPa at 15.0 °C. On the following day, the temperature increased to 25.9 °C, and the new volume was 221.2 mL. What was the atmospheric pressure on this day?A. 100.2 kPa B. 101.5 kPa C. 98.7 kPa D. 99.9 kPa

Answer :

Final answer:

Explanation:

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Other Questions

A 225 mL gas syringe was at a pressure of 99.3 kPa at 15.0 °C. On the following day, the temperature increased to 25.9 °C, and the new volume was 221.2 mL. What was the atmospheric pressure on this day?

A. 100.2 kPa
B. 101.5 kPa
C. 98.7 kPa
D. 99.9 kPa