Answer :
Final answer:
The acceleration of the satellite is 8.088 m/s^2 and the period is 5979 seconds or 99.65 minutes.
Explanation:
To find the acceleration of the satellite, we can use the equation for centripetal acceleration: a = v^2 / r. Plugging in the values, we get a = (7.58 x 10^3)^2 / 7.1 x 10^6. Calculating this, we find that the acceleration is approximately 8.088 m/s^2.
To find the period of the satellite, we can use the equation T = 2πr / v. Plugging in the values, we get T = 2π x 7.1 x 10^6 / 7.58 x 10^3. Calculating this, we find that the period is approximately 5979 seconds or 99.65 minutes.
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