Answer :
Final answer:
The question is about a titration process where the acid, benzoic acid, is neutralized by a base, NaOH. By calculating the moles of benzoic acid and NaOH, we can figure out their concentrations and hence, determine the pH of the final solution.
Explanation:
The question is asking about a chemical process known as titration where a solution of known concentration (NaOH in this case) is used to determine the concentration of an unknown solution (benzoic acid in our instance). The benzoic acid dissolves in water to form a solution that can dissociate to produce H+ ions, thus, it is an acid. Its molar mass is about 122.12 g/mol. The mole of the benzoic acid is therefore 2.359 g / 122.12 g/mol = 0.0193 mol.
Given that the NaOH neutralizes the acid, we can assume that equivalent moles of NaOH are required and hence, the volume of NaOH needed can be calculated as follows: 0.0193 mol / 0.140 N = 0.138 L.
After all the acid has been neutralized, the excess base determines the pH. The molarity of excess NaOH can be calculated by (Volume of NaOH - volume used to neutralize acid)/total volume. The pH of the solution can then be determined by using the formula pH = 14 - pOH where pOH is the negative logarithm of the hydroxide ion concentration.
Learn more about Titration here:
https://brainly.com/question/31271061
#SPJ11
