High School

A 150-kg object takes 1.5 minutes to travel a 2,500-meter straight path. It begins the trip traveling 120 meters per second and decelerates to a velocity of 20 meters per second.

What was its acceleration?

Responses:

A. \(-1.11 \, \text{m/s}^2\)

B. \(-0.3 \, \text{m/s}^2\)

C. \(+1.11 \, \text{m/s}^2\)

D. \(+80 \, \text{m/s}^2\)

Answer :

Answer: So the answer is (A) -1.11 m/s^2.

Explanation: To solve this problem, we need to use the formula for average acceleration, which is given by:

a = (vf - vi) / t

Where a is the acceleration, vf is the final velocity, vi is the initial velocity, and t is the time.

Plugging in the values given in the problem, we get:

a = (20 m/s - 120 m/s) / (1.5 minutes * 60 seconds/minute) = -100 m/s / 90 seconds = -1.11 m/s^2

So the answer is (A) -1.11 m/s^2.

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