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------------------------------------------------ A 15 mL single-dose vial of potassium phosphates contains 45 mM of phosphate and 66 mEq of potassium. How many mL are needed for a dose of 40 mEq of potassium?

Answer :

You would need approximately 9.09 mL of the potassium phosphate solution to deliver a dose of 40 mEq of potassium.

To determine how many milliliters are needed for a dose of 40 mEq of potassium, we can use the information provided on the potassium concentration in the vial.

  1. Understand the Concentration:
    The 15 mL single dose vial contains 66 mEq of potassium in total. This means that the entire 15 mL of the solution contains the full amount of potassium available.

  2. Determine mEq per mL:
    To find the concentration of potassium in mEq per mL, we can calculate:
    [tex]\text{Concentration (mEq/mL)} = \frac{66 \text{ mEq}}{15 \text{ mL}} = 4.4 \text{ mEq/mL}[/tex]

  3. Calculate the Volume Needed for 40 mEq:
    Next, we set up a proportion to find out how many mL of the solution is needed to obtain a dose of 40 mEq:
    [tex]\text{Volume needed (mL)} = \frac{\text{Desired mEq}}{\text{Concentration (mEq/mL)}} = \frac{40 \text{ mEq}}{4.4 \text{ mEq/mL}}[/tex]
    [tex]\text{Volume needed (mL)} = 9.09 \text{ mL}[/tex]

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