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A 114-gram cube of ice at 0°C is dropped into 1.0 kg of water that was originally at 79°C.

What is the final temperature of the water after the ice has melted?

Answer :

Final answer:

The final temperature of the water after the ice has melted is 9211.5 °C.

Explanation:

To find the final temperature of the water after the ice has melted, we need to calculate the amount of heat absorbed by the ice and the amount of heat transferred to the water.

First, let's calculate the heat absorbed by the ice using the equation Q = m * L, where Q is the heat absorbed, m is the mass of the ice, and L is the latent heat of fusion for water.

Given that the mass of the ice is 114−9 kg and the latent heat of fusion for water is 334,000 J/kg, we can calculate the heat absorbed by the ice as follows:

Q = (114−9 kg) * (334,000 J/kg) = 3.82 * 10^7 J

Next, let's calculate the amount of heat transferred to the water using the equation Q = m * c * ΔT, where Q is the heat transferred, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.

Given that the mass of the water is 1.0 kg, the specific heat capacity of water is 4,186 J/kg·°C, and the initial temperature of the water is 79 ∘C, we can calculate the change in temperature as follows:

Q = (1.0 kg) * (4,186 J/kg·°C) * ΔT

3.82 * 10^7 J = (1.0 kg) * (4,186 J/kg·°C) * ΔT

ΔT = (3.82 * 10^7 J) / (1.0 kg * 4,186 J/kg·°C) = 9132.5 °C

Finally, we can calculate the final temperature of the water by adding the change in temperature to the initial temperature:

Final temperature = 79 ∘C + 9132.5 °C = 9211.5 °C

Therefore, the final temperature of the water after the ice has melted is 9211.5 °C.

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