High School

A 102.3 kg archer is standing on level ice (neglecting friction) and fires a 99 g arrow to the right at 104.2 m/s. What is the recoil speed of the archer?

Report your answer to at least the thousandth's place.

Answer :

Conservation of momentum

Pix = Pfx

m1= Archer's mass = 102.3 kg

v1 = Archer's velocity =

m2 = arrow's mass = 99g = 0.099 kg

v2f= arrow's velocity = 104.2 m/s

0= m1 v1 + m2 v2

V1= -( m2/m1) v2

V1 = - (0.099 kg /102.3 kg) *104.2 m/s

V1= - 0.1008 m/s

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