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A 10 lb dog needs to be fed 3 ounces of food per day. What is this in grams?

A. 126.6
B. 7.2
C. 32.5
D. 97.5

Answer :

Sure! Let's work through the problem step-by-step.

We need to find out how many grams of food a 10 lb dog needs per day if it needs to be fed 3% ounces of food for each pound it weighs.

### Step 1: Calculate the Daily Food in Ounces

First, we determine how many ounces of food the dog needs in total.

- The dog weighs 10 pounds.
- The dog needs 3% ounces of food for each pound.

The total food in ounces is calculated by multiplying the weight of the dog by 3%:

[tex]\[ \text{Total ounces} = 10 \text{ lb} \times 0.03 \text{ ounces/lb} = 0.3 \text{ ounces} \][/tex]

### Step 2: Convert Ounces to Grams

Next, we convert the food amount from ounces to grams. The conversion factor is:

1 ounce = 28.3495 grams

So, the amount in grams is:

[tex]\[ \text{Total grams} = 0.3 \text{ ounces} \times 28.3495 \text{ grams/ounce} \approx 8.50485 \text{ grams} \][/tex]

### Conclusion

The dog needs approximately 8.5 grams of food per day. This matches with none of the given options directly, but if we are to choose based on rounding, none of the options precisely matches. Thus, based on our calculated value of approximately 8.5 grams, none of the provided choices directly fits, but 7.2 is the closest among them without being correct.