High School

8. Two rescuers are 20 meters apart and spot a victim up a hillside. The first rescuer's angle of elevation to the victim is 50°, and he is 17.5 meters from the victim. How far is the second rescuer from the victim? Draw a diagram and show all work. (8 points)

9. Find the area of the triangle with sides 2 cm, 4 cm, and 5 cm. Show work and formula. (8 points)

Answer :

Final answer:

For question 8, by using the cosine rule, we can find the distance of the second rescuer to the victim.

For question 9, using the formula for the area of a right triangle (0.5*base*height), we find the area to be 4 cm².

Explanation:

To solve question 8, we can use trigonometry. For the first rescuer, the angle of elevation to the victim is 50° and he is 17.5 meters from the victim. We can apply the cosine rule in this case, which states that cosA = (b²+c²-a²) / 2bc.

In the given question, a is 20 m (distance between the two rescuers), b is 17.5 m (distance from first rescuer to the victim) and angle A is the angle of elevation from the first rescuer to the victim, which is 50°. We are to find c (distance from second rescuer to the victim).

Plugging the known values into the formula, we get cos50 = (20² + 17.5² - c²) / (2*20*17.5). Solve for c to find the distance of the second rescuer to the victim.

For question 9, if we have a triangle with sides 2 cm, 4 cm, and 5 cm, it is a right triangle (since 5² = 2² + 4², satisfying the Pythagorean theorem). Here, we simply calculate the area of this triangle using the formula 0.5*base*height. Hence, the area of the triangle is 0.5*2*4 = 4 cm².

Learn more about right triangle

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