Answer :
Let's solve the problem step-by-step to find out how many times you need to regroup when subtracting 426 from 913.
### Step 1: Subtracting the ones place
- Look at the ones place:
- 3 (from 913) and 6 (from 426)
- Since 3 is less than 6, you need to regroup:
- Borrow 1 from the tens place, making 3 into 13.
- Subtract 6 from 13:
- 13 - 6 = 7
- That is 1 regroup.
### Step 2: Subtracting the tens place
- After borrowing, the tens place is now 0 (because you borrowed 1, making 1 become 0).
- Compare the tens place:
- 0 (from 913 now) and 2 (from 426)
- Since 0 is less than 2, you need to regroup again:
- Borrow 1 from the hundreds place, making 0 into 10.
- Subtract 2 from 10:
- 10 - 2 = 8
- That is another regroup.
### Step 3: Subtracting the hundreds place
- After borrowing, the hundreds place is now 8 (because you borrowed 1, making 9 become 8).
- Compare the hundreds place:
- 8 (from 913 now) and 4 (from 426)
- Since 8 is not less than 4, you do not need to regroup here.
- Subtract 4 from 8:
- 8 - 4 = 4
### Conclusion
During the subtraction process, you regrouped twice:
1. From the ones place to the tens place.
2. From the tens place to the hundreds place.
So, you need to regroup 2 times when subtracting 426 from 913.
### Step 1: Subtracting the ones place
- Look at the ones place:
- 3 (from 913) and 6 (from 426)
- Since 3 is less than 6, you need to regroup:
- Borrow 1 from the tens place, making 3 into 13.
- Subtract 6 from 13:
- 13 - 6 = 7
- That is 1 regroup.
### Step 2: Subtracting the tens place
- After borrowing, the tens place is now 0 (because you borrowed 1, making 1 become 0).
- Compare the tens place:
- 0 (from 913 now) and 2 (from 426)
- Since 0 is less than 2, you need to regroup again:
- Borrow 1 from the hundreds place, making 0 into 10.
- Subtract 2 from 10:
- 10 - 2 = 8
- That is another regroup.
### Step 3: Subtracting the hundreds place
- After borrowing, the hundreds place is now 8 (because you borrowed 1, making 9 become 8).
- Compare the hundreds place:
- 8 (from 913 now) and 4 (from 426)
- Since 8 is not less than 4, you do not need to regroup here.
- Subtract 4 from 8:
- 8 - 4 = 4
### Conclusion
During the subtraction process, you regrouped twice:
1. From the ones place to the tens place.
2. From the tens place to the hundreds place.
So, you need to regroup 2 times when subtracting 426 from 913.
