Answer :
6 coulombs of charge flowing in a bulb filament powered by a 6-volt battery for 2 seconds results in the dissipation of 18 watts of power. Therefore, the correct option is 4.
The question involves finding the energy used by a bulb filament when 6 coulombs of charge flow through it, which is powered by a 6-volt battery over a period of 2 seconds. The electrical energy (extbf{work}) done by the electric current is given by the formula
Work (W) = Voltage (V) * Charge (Q).
To calculate this, we multiply the voltage of the battery by the amount of charge that has flowed in the given time. Thus, the energy used is
W = 6 V * 6 C = 36 joules.
However, since this energy is used over a period of 2 seconds, power, which is the rate at which energy is used, is the correct answer. Power (P) is calculated by
P = W/t,
where t is time.
Here, P = 36 J / 2 s = 18 watts. Therefore, the correct answer is 18 watts.
