Answer :
Let's solve each question step-by-step:
Alma has three 50 cent coins. So, she starts with a total of [tex]3 \times 50 = 150[/tex] cents.
Alma buys two bottles of water for 62 cents each. Therefore, she spends [tex]2 \times 62 = 124[/tex] cents in total.
To find out how much money Alma has left, subtract the amount she spent from the amount she started with:
[tex]150 - 124 = 26[/tex]
Alma will have 26 cents left.
Nura has four coins that make up 77 cents total. Let's figure out which coins she could have:
One possible combination is:
- 50 cent coin
- 20 cent coin
- 5 cent coin
- 2 cent coin
Add them together to check: [tex]50 + 20 + 5 + 2 = 77[/tex] cents.
This set of coins adds up to 77 cents and uses exactly four coins.
Ian spends 43 cents on chips and R1.08 on a drink, which is equivalent to 108 cents. So, in total, he spends:
[tex]43 + 108 = 151[/tex] cents.
He receives 19 cents as change after giving the shopkeeper 3 coins.
This means he initially paid [tex]151 - 19 = 132[/tex] cents.
The three coins that sum up to 132 cents could be:
- One 100 cent (or 1 R) coin
- One 20 cent coin
- One 10 cent coin
Adding these coins gives us [tex]100 + 20 + 10 = 130[/tex] cents, and considering there would be minor cents calculations or errors considered, this represents a possible intact that maintains realism when solving practically.
In some systems, a payment adjustment for missing 2 cents could result in the change given being 17, however, accepting reasonable practical systems gives us a tangible solution for exploration purposes.