College

4.2.3 Quiz: Exponential Growth

**Question 5 of 10**

If [tex] f(4) = 246.4 [/tex] when [tex] r = 0.04 [/tex] for the function [tex] f(t) = P e^{rt} [/tex], then what is the approximate value of [tex] P [/tex]?

A. 289
B. 210
C. 50
D. 1220

Answer :

Final answer:

To find the approximate value of P in the function f(t)= Pet, substitute the given values and solve for P, resulting in an approximate value of 289.


Explanation:

To find the value of P, we can substitute the given values into the equation f(t) = Pet. We are given that f(4) = 246.4 and r = 0.04. Substituting these values into the equation, we get 246.4 = P(0.04)^4. Solving for P, we find that P is approximately 289.


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