Answer :
Final answer:
By applying Boyle's Law (P₁V₁ = P₂V₂), we can determine that the final pressure of the gas, once it's been compressed from 8.00 L to 2.00 L, is 16.00 atm.
Explanation:
The problem you're trying to solve is a classic illustration of Boyle's Law, which states that for a fixed amount of gas kept at a constant temperature, the volume is inversely proportional to the pressure. In other words, as volume decreases, pressure increases, and vice versa. Let's apply this law to your problem.
Boyle's Law is typically represented as P₁V₁ = P₂V₂, where P represents pressure, V represents volume, and the subscripts 1 and 2 signify the initial and final states, respectively.
You're given the initial pressure (P₁ = 4.00 atm), the initial volume (V₁ = 8.00 L), and the final volume (V₂ = 2.00 L). The final pressure (P₂) is what you're trying to find.
Plugging in these values into Boyle's Law equation gives us:
4.00 atm*8.00 L = P₂ * 2.00 L
Solving for P₂ (final pressure), we get:
P₂ = (4.00 atm*8.00 L) / 2.00 L = 16.00 atm
So, the resulting pressure of the gas after it is compressed from 8.00 L to 2.00 L at constant temperature is 16.00 atm.
Learn more about Boyle's Law here:
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