High School

4. The ratio [tex]$k_b/k_m$[/tex] is called the catalytic efficiency of an enzyme. Use the data in Chapter 17F.2 (pg 760) to calculate the catalytic efficiency of carbonic anhydrase.

Answer :

To calculate the catalytic efficiency of the carbonic anhydrase enzyme, simply find the turnover number (kb) and the Michaelis constant (km) in the provided text and calculate the ratio by dividing kb by km.

Catalytic efficiency is a measure of how effectively an enzyme converts substrates into products, and the ratio kb/km is often used to express it. Catalytic efficiency can be calculated by using data on the rates at which the enzyme carbonic anhydrase functions. Once we have the data of kb (turnover number) and km (Michaelis constant) from chapter 17f.2, the ratio kb/km can be calculated simply by dividing kb by km.

Carbonic anhydrase, the enzyme in question here, is known for catalyzing the reaction that causes carbon dioxide and water to form carbonic acid. Like all enzymes, it is a catalytic protein that speeds up chemical reactions by lowering their activation energy. The rate at which this occurs can be influenced by a range of factors, including environmental ones like pH and temperature.

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Final answer:

The catalytic efficiency of an enzyme is a measure of its ability to convert substrate into product. The provided information doesn't include the necessary data to calculate the catalytic efficiency of carbonic anhydrase. A higher catalytic efficiency indicates a more efficient enzyme.

Explanation:

The catalytic efficiency of an enzyme can be calculated by the ratio kb/km, where kb is the rate constant of the enzyme-substrate complex formation and km is the Michaelis constant. To calculate the catalytic efficiency of carbonic anhydrase, we need specific data from Chapter 17F.2, page 760. Unfortunately, the provided information doesn't include the required data. However, in general, a higher catalytic efficiency indicates that the enzyme can convert substrate molecules into products more rapidly, making the enzyme more efficient.

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