High School

2 scored 8 out of 40 in Term 1 and scored 12 out of 40 in Term 2. If the average pass percentage is 35% of the average of all terms, how much should 2 score in Term 3 out of 100?

Answer :

To find out how much "2" should score in Term 3 out of 100 to pass, we need to determine the required average for all terms and then solve for the Term 3 score. Let's break it down step by step.

Step 1: Calculate the total scores and average so far.

  • Term 1 Score: 8 out of 40
  • Term 2 Score: 12 out of 40

Let's find the average score of these two terms.

The total score for Term 1 and Term 2 is:
[tex]8 + 12 = 20[/tex]

The total possible score for the two terms is:
[tex]40 + 40 = 80[/tex]

So the average percentage score for the first two terms is:
[tex]\frac{20}{80} \times 100\% = 25\%[/tex]

Step 2: Determine the required average for passing.

The average pass percentage is 35%. This means the average score over the three terms (Term 1, Term 2, and Term 3 combined) should be 35%.

Step 3: Set up the equation to find the required Term 3 score.

Let’s denote the Term 3 score out of 100 as [tex]x[/tex]. The equation for the average score over the three terms is:
[tex]\frac{20 + x}{80 + 100} \times 100\% = 35\%[/tex]

This simplifies to:
[tex]\frac{20 + x}{180} \times 100 = 35[/tex]

Solving for [tex]x[/tex]:
[tex]\frac{20 + x}{180} = 0.35[/tex]

[tex]20 + x = 0.35 \times 180[/tex]

[tex]20 + x = 63[/tex]

[tex]x = 63 - 20[/tex]

[tex]x = 43[/tex]

Therefore, "2" should score 43 out of 100 in Term 3 to achieve an average of 35% across all terms.