The change in momentum of the hammer head is -1.2 kg m/s. The impulse given to the nail is -1.2 kg m/s. The average force between the hammer and the nail is -800 N.
(a) The change in momentum of the hammer head can be calculated using the formula:
Change in Momentum = Mass x Final Velocity - Mass x Initial Velocity
Substituting the given values, the change in momentum is:
Change in Momentum = 0.15 kg x 0 m/s - 0.15 kg x 8.0 m/s = -1.2 kg m/s
(b) The impulse given to the nail can be calculated using the formula:
Impulse = Force x Time
Since the hammer head stops after hitting the nail, the impulse given to the nail would be equal to the change in momentum of the hammer head, which is -1.2 kg m/s.
(c) The average force between the hammer and the nail can be calculated using the formula:
Average Force = Impulse / Time
Substituting the given values, the average force is:
Average Force = -1.2 kg m/s / 0.0015 s = -800 N
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