What is the value of \( x_9 \) for the following assembly code?

```assembly
add x9, x0, x1
```

a) \( x_9 = x_0 + x_1 \)

b) \( x_9 = x_0 - x_1 \)

c) \( x_9 = x_0 \times x_1 \)

d) \( x_9 = x_0 / x_1 \)

Answer :

Final answer:

The assembly code instruction 'add x9, x0, x1' denotes that x₉ is assigned the value of x₀ plus x₁. The answer is a) (x₉ = x₀ + x₁), which represents an addition operation in many RISC assembly languages.

Explanation:

The instruction in the assembly code is add x9, x0, x1, which clearly indicates that the operation being performed is an addition. Therefore, the value of x₉ after the instruction execution will be the sum of the values contained in x₀ and x₁. In terms of the options provided, the correct answer is a) (x₉ = x₀ + x₁). This instruction format is common in many assembly languages associated with RISC (Reduced Instruction Set Computer) architectures where the first operand after the instruction mnemonic represents the destination register, and the subsequent operands represent the source registers.

In assembly language programming, instructions are often very literal, and the provided code snippet is a direct representation of an arithmetic operation. The 'add' mnemonic stands for 'addition', meaning that the instruction performs a simple arithmetic addition of the values in registers x₀ and x₁, and then stores the result in register x₉. No other arithmetic operations like subtraction, multiplication, or division are indicated in this assembly instruction.