Answer :
Final answer:
The molarity of the resultant NaOH solution after mixing 2.5 liters of 1M NaOH with 3 liters of 0.5M NaOH is approximately 0.73 M, or closest to answer choice b) 0.75M.
Explanation:
To find the molarity of the resultant NaOH solution when mixing two solutions of different molarities, you can use the formula for dilution which is C1V1 + C2V2 = Cfinal(V1 + V2), where C stands for molarity and V stands for volume.
In this case, the molarity and volumes of the two NaOH solutions are:
- C1 = 1M, V1 = 2.5 L
- C2 = 0.5M, V2 = 3 L
Plugging these into the formula gives:
(1M
2.5 L) + (0.5M
3 L) = Cfinal(2.5 L + 3 L)
Cfinal = (2.5 mol + 1.5 mol) / (5.5 L)
Cfinal = 4 mol / 5.5 L = 0.727 M
Rounded to two significant figures, the molarity of the resultant solution is 0.73 M, which matches closest to answer option b) 0.75M.
