Given the following forces and values:

- [tex]F = 24.94 \, \text{N}[/tex] (force of friction)
- [tex]F_n = 76.556 \, \text{N}[/tex] (normal force)
- [tex]F_a = 62.9 \, \text{N}[/tex] (applied force)
- [tex]F = 76.556 \, \text{N}[/tex] (force due to gravity)
- [tex]M = 7.82 \, \text{kg}[/tex] (mass)
- [tex]A = 4.83 \, \text{m/s}^2[/tex] (acceleration)
- [tex]F_{\text{net}} = 37.9 \, \text{N}[/tex] (net force)

(Note: It appears there is a repetition or mistake with the forces labeled "F" and "Fₙ" having the same value. Please check for clarity.)

The net force (Fₙₑₜ) acting on an object is the vector sum of all individual forces acting on it. Given the values provided, the net force is calculated by subtracting the force of friction (F = 24.94 N) from the applied force (Fₐ = 62.9 N). Mathematically, Fₙₑₜ = Fₐ - F = 62.9 N - 24.94 N = 37.96 N. Rounding off, the net force is 37.9 N.

The net force of 37.9 N implies that there is an unbalanced force acting on the object, causing it to accelerate. This acceleration (A) is given as 4.83 m/s². Newton's second law states that the net force acting on an object is equal to the mass (M) of the object multiplied by its acceleration (Fₙₑₜ = M × A). Substituting the given values, M = 7.82 kg and A = 4.83 m/s², we find that Fₙₑₜ = 7.82 kg × 4.83 m/s² = 37.90 N.

Thus, the final answer confirms that the net force acting on the object is 37.9 N, indicating an unbalanced force leading to the observed acceleration.