High School

2.00 liters of nitrogen at 215.91 torr is mixed with 2.00 liters of helium at 53.46 torr and a third gas, oxygen. Together, the three gases exert a pressure of 1,173.99 torr in a 2.00-liter container. What is the pressure of the oxygen gas in torr?

Answer :

The pressure of oxygen gas in a mixture of nitrogen and helium is to be determined.

The three gases are present in a 2.00 liter container, and their individual pressures are known. The total pressure exerted by the three gases in the container is also given.

In order to determine the pressure of the oxygen gas, we will need to apply Dalton's law of partial pressures. According to this law, the total pressure of a mixture of gases is equal to the sum of the partial pressures of the individual gases. Mathematically, we can express this as:

P_total = P_1 + P_2 + P_3

where P_total is the total pressure, and P_1, P_2, and P_3 are the partial pressures of the gases.

In the given problem, we know the partial pressures of nitrogen and helium, and the total pressure of the mixture. Therefore, we can write:

P_total = P_N2 + P_He + P_O2

Substituting the values given in the problem, we get:

1173.99 torr = 215.91 torr + 53.46 torr + P_O2

Solving for P_O2, we get:

P_O2 = P_total - P_N2 - P_He

P_O2 = 1173.99 torr - 215.91 torr - 53.46 torr

P_O2 = 904.62 torr

Therefore, the pressure of the oxygen gas in the mixture is 904.62 torr.

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