Answer :
The correct answer is option e). 108g of aluminium reacts with 1.21kg of copper chloride to produce 381.3 grams copper.
To determine how much copper is produced when 108 grams of aluminium reacts with 1.21 kilograms (1210 grams) of copper chloride, we start by writing the balanced chemical equation for the reaction:
[tex]\[ 2 Al + 3 CuCl_2 \rightarrow 3 Cu + 2 AlCl_3 \][/tex]
From the equation, we can see that 2 moles of aluminium react with 3 moles of copper chloride to produce 3 moles of copper.
1. Convert the masses to moles:
[tex]\text{ Moles} \) of aluminium \( = \frac{108 \text{ g}}{27 \text{ g/mol}} = 4 \text{ moles} \) (molar mass of aluminum is 27 g/mol)[/tex]
[tex]\text{Moles}\ \text{of}\ \text{copper}\ \text{chloride}\ \( = \frac{1210 \text{ g}}{134.45 \text{ g/mol}} \approx 9 \text{ moles} \) (molar mass of copper chloride is 134.45 g/mol)[/tex]
2. Determine the theoretical yield of copper:
According to the balanced equation, 2 moles of aluminium produce 3 moles of copper.
Therefore, [tex]\( 4 \text{ moles of Al} \times \frac{3 \text{ moles of Cu}}{2 \text{ moles of Al}} = 6 \text{ moles of Cu} \).[/tex]
3. Convert moles of copper to grams:
[tex]\text{Moles}\ \text{of}\ \text{copper}\ \( = 6 \text{ moles} \times 63.55 \text{ g/mol} = 381.3 \text{ g} \) (molar mass of copper is 63.55 g/mol)[/tex]
The complete question is:
108g of aluminium reacts with 1.21kg of copper chloride to produce copper.
a) 64g
b) 80g
c) 96g
d) 112g
e) 381.3g
Final answer:
When 108g of aluminum reacts with 1.21kg of copper chloride, the mass of copper produced is 127g.
Explanation:
When 108g of aluminum reacts with 1.21kg of copper chloride, the reaction produces copper. To find the mass of copper produced, we need to determine the limiting reactant and calculate the amount of copper formed from it. First, we convert the masses of aluminum and copper chloride to moles using their molar masses. Then, we compare the moles of aluminum and copper chloride to determine the limiting reactant. Finally, we use the balanced equation to calculate the moles of copper formed and convert it to grams.
The molar mass of aluminum is 26.98 g/mol and the molar mass of copper chloride (CuCl2) is 134.45 g/mol. Converting 108g of aluminum to moles:
108g Al * (1 mol Al / 26.98 g Al) = 4.00 mol Al
Converting 1.21kg of copper chloride to moles:
1.21kg CuCl2 * (1000 g / 1kg) * (1 mol CuCl2 / 134.45 g CuCl2) = 8.99 mol CuCl2
Comparing the moles of aluminum and copper chloride:
Aluminum: 4.00 mol
Copper chloride: 8.99 mol
We can see that aluminum is the limiting reactant because it has fewer moles than copper chloride. The balanced equation shows that 2 moles of aluminum produce 1 mole of copper, so:
4.00 mol Al * (1 mol Cu / 2 mol Al) = 2.00 mol Cu
Finally, converting the moles of copper to grams:
2.00 mol Cu * (63.55 g Cu / 1 mol Cu) = 127 g Cu
Therefore, the mass of copper produced in this reaction is 127g.
