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------------------------------------------------ The combined SAT scores for the students at a local high school are normally distributed with a mean of 1496 and a standard deviation of 292. The local college includes a minimum score of 1321 in its admission requirements.

What percentage of students from this school earn scores that fail to satisfy the admission requirement? Write your answer as a decimal using the appropriate rounding rule.

The z-score formula is:
z = (X - μ) / σ
Where z is the z-score, X is the value we want to find the percentage for, μ is the mean, and σ is the standard deviation.

Step 1: Calculate the z-score.
z = (1321 - 1496) / 292
z = (-175) / 292
z ≈ -0.60

Step 2: Find the proportion of students with a z-score below -0.60. You can use a z-table or an online calculator for this. For z = -0.60, the proportion is approximately 0.2743.

Step 3: Convert the proportion to a percentage.
0.2743 * 100 = 27.43%

Step 4: Round the percentage using the appropriate rounding rule. In this case, let's round to two decimal places.
27.43% ≈ 27.43%

So, approximately 27.43% of students from this high school earn scores that fail to satisfy the admission requirement of the local college.

To learn more about percentage : brainly.com/question/29306119

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