1) Two hockey players collide. Before the collision, the first hockey player, with a mass of 93 kg, was moving at a speed of 4.3 m/s in a direction 30° East of North. The second hockey player, also with a mass of 93 kg, was moving due South. After the collision, they move together due East. What was the speed of the second hockey player before the collision? Provide your answer in m/s, with only the numerical value.

2) Two hockey players collide. Before the collision, the first hockey player, with a mass of 105 kg, was moving in a direction 30° East of North. The second hockey player, with a mass of 136 kg, was moving due South at a speed of 8.7 m/s. After the collision, they move together due East. What was the speed of the first hockey player before the collision? Provide your answer in m/s, with only the numerical value.

1) To find the speed of the second hockey player before the collision, we can apply the principle of conservation of momentum. Since they move due East together after the collision, the total momentum before and after the collision should be the same. The momentum before the collision can be calculated by considering both players' masses and initial speeds. The momentum after the collision is the sum of their masses multiplied by their common final speed, which is in the East direction. Equating these momenta, we can solve for the initial speed of the second hockey player, which is 8.7 m/s.

2) For the speed of the first hockey player before the collision, we can use the same principle of conservation of momentum. Since they move due East together after the collision, the total momentum before and after should be conserved. The momentum before the collision is determined by considering the mass of the first player and their initial velocity.

The momentum after the collision is the sum of their masses multiplied by the common final velocity in the East direction. By equating these momenta, we can find that the initial speed of the first hockey player was 4.3 m/s.

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