High School

1. $15 \div 3$
2. $36 \div 6$
3. $12 \div 3$
4. $49 \div 7$

Divide one digit number by a one digit number [long division method]

1. $66 \div 6$
2. $84 \div 2$
3. $87 \div 3$
4. $95 \div 3$

Divide using long division method.

Answer :

Let's solve each division problem step by step using the long division method.

  1. 66 divided by 6:

    Start by dividing the first digit of 66 by 6. Since 6 goes into 6 exactly 1 time, write 1 above the line.

    [tex]\begin{array}{c|l}
    1 & 66 \\
    \hline
    & 66 \\
    & -6 \\
    & \underline{0}
    \end{array}[/tex]

    Now, bring down the second digit, which is another 6. Repeat the process: 6 goes into 6 exactly 1 time, so we write another 1 above the line. The answer is 11.

  2. 84 divided by 2:

    Start with the first digit:

    [tex]\begin{array}{c|l}
    4 & 84 \\
    \hline
    & 84 \\
    & -8 \\
    & \underline{0}
    \end{array}[/tex]

    2 goes into 8 four times. Then, bring down the next digit, 4. 2 goes into 4 exactly 2 times, so write 2 above the line. The answer is 42.

  3. 87 divided by 3:

    Start by considering how many times 3 goes into the first digit, 8.

    [tex]\begin{array}{c|l}
    2 & 87 \\
    \hline
    & 66 \\
    & -6 \\
    & 27 \\
    & -27 \\
    & \underline{0}
    \end{array}[/tex]

    3 goes into 8 two times with a remainder. Bring down the next digit, 7. 3 goes into 27 exactly 9 times. The answer is 29.

  4. 95 divided by 3:

    Start by seeing how many times 3 goes into 9:

    [tex]\begin{array}{c|l}
    3 & 95 \\
    \hline
    & 9 \\
    & -9 \\
    & 5 \\
    & -3 \\
    & 20
    \end{array}[/tex]

    3 goes into 9 three times, and then 3 goes into 5 once with a remainder of 2. The answer is 31 with a remainder of 2.

In summary, the results of the long division are as follows:

  1. 66 divided by 6 is 11.

  2. 84 divided by 2 is 42.

  3. 87 divided by 3 is 29.

  4. 95 divided by 3 is 31 with a remainder of 2.

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