High School

You wish to test the following claim ([tex]H_{a}[/tex]) at a significance level of [tex]\alpha=0.001[/tex]:

[tex]
\[
\begin{array}{l}
H_{0}: \mu = 87.4 \\
H_{a}: \mu > 87.4
\end{array}
\]
[/tex]

You believe the population is normally distributed, but you do not know the standard deviation. You obtain the following sample of data:

[tex]
\[
\begin{array}{|r|r|r|r|r|}
\hline 87.8 & 106.4 & 77.9 & 67.7 & 90.8 \\
\hline 110 & 96 & 70 & 82.9 & 84.7 \\
\hline 72.5 & 108 & 97.5 & 120.2 & 92.8 \\
\hline 92.1 & 58.7 & 89.5 & 86.4 & 98.4 \\
\hline 108 & 92.8 & 75.8 & 120.2 & 87.1 \\
\hline 87.8 & 86.4 & 107.2 & 97.9 & 86.1 \\
\hline 97.5 & 86.4 & 70 & 71.8 & 104.3 \\
\hline 72.5 & 76.3 & 78.3 & 86.8 & 91.4 \\
\hline 70 & 81 & 95.6 & 80.1 & 70.9 \\
\hline 105 & 107.2 & 75.8 & 83.6 & 86.8 \\
\hline
\end{array}
\]
[/tex]

What is the test statistic for this sample? (Report answer accurate to three decimal places.)

Test statistic = [tex]\square[/tex]

What is the p-value for this sample? (Report answer accurate to four decimal places.)

P-value = [tex]\square[/tex]

The [tex]p[/tex]-value is...

A. less than (or equal to) [tex]\alpha[/tex]

B. greater than [tex]\alpha[/tex]

Answer :

To solve this question, we need to perform a hypothesis test for a single sample mean. The claim we want to test is whether the population mean [tex]\(\mu\)[/tex] is greater than 87.4. We have a sample and need to calculate the test statistic and p-value based on this data.

Here’s a step-by-step solution:

1. Set Up the Hypotheses:
- Null Hypothesis ([tex]\(H_0\)[/tex]): [tex]\(\mu = 87.4\)[/tex]
- Alternative Hypothesis ([tex]\(H_a\)[/tex]): [tex]\(\mu > 87.4\)[/tex] (This is a right-tailed test)

2. Sample Data:
- We have a set of 50 data points from the sample.

3. Calculate the Sample Mean and Standard Deviation:
- Compute the mean ([tex]\(\bar{x}\)[/tex]) of the sample data.
- Compute the sample standard deviation ([tex]\(s\)[/tex]).

4. Determine the Test Statistic:
The test statistic for a t-test when the population standard deviation is unknown is calculated as:
[tex]\[
t = \frac{\bar{x} - \mu_0}{s / \sqrt{n}}
\][/tex]
where:
- [tex]\(\bar{x}\)[/tex] is the sample mean.
- [tex]\(\mu_0\)[/tex] is the mean under the null hypothesis (87.4).
- [tex]\(s\)[/tex] is the sample standard deviation.
- [tex]\(n\)[/tex] is the sample size.

5. Calculate the P-Value:
Since this is a right-tailed test, the p-value is the probability that the test statistic is greater than the calculated value.

6. Decision Making:
Compare the p-value to the significance level [tex]\(\alpha = 0.001\)[/tex]:
- If the p-value is less than or equal to [tex]\(\alpha\)[/tex], we reject the null hypothesis.
- If the p-value is greater than [tex]\(\alpha\)[/tex], we do not reject the null hypothesis.

Based on the calculations, the results are:
- Test Statistic: 0.614 (rounded to three decimal places)
- P-Value: 0.2712 (rounded to four decimal places)
- Conclusion: The p-value is greater than [tex]\(\alpha = 0.001\)[/tex], so we fail to reject the null hypothesis. Therefore, there is not enough evidence to support the claim that the population mean is greater than 87.4.