Answer :
When 10.0 g of NaOH (strong base) is placed into 2.00 L of water (final solution volume is 2.00 L), a solution is formed.The molarity of the resulting solution is 0.125 M.
When 10.0 g of NaOH (strong base) is placed into 2.00 L of water (final solution volume is 2.00 L), a solution is formed.
The molarity of the resulting solution can be found by using the formula:
Molarity = (Number of moles of solute) / (Volume of solution in liters)Initially, we must calculate the number of moles of NaOH present in 10.0 g of NaOH using the molar mass of NaOH:Number of moles of NaOH = (Mass of NaOH) / (Molar mass of NaOH)Molar mass of NaOH = 23.0 + 16.0 + 1.0 = 40.0 g/mol (atomic masses of Na, O, and H respectively)
Number of moles of NaOH = 10.0 g / 40.0 g/mol = 0.25 mol NaOHThe volume of the resulting solution is 2.00 L. Substituting the values in the molarity formula: Molarity = 0.25 mol / 2.00 L = 0.125 M.
The molarity of the resulting solution is 0.125 M.
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