You measure the current through a [tex]38.1 \, \Omega[/tex] resistor to be [tex]55 \, \text{mA}[/tex]. What is the potential difference across the contacts of the resistor?

The potential difference across a 38.1-ohm resistor with a current of 55 milliamps flowing through it is calculated using Ohm's Law as approximately 2.0955 volts.

Explanation:

To calculate the potential difference across the contacts of a resistor using Ohm's Law, you would use the formula V = I × R, where V is the voltage in volts, I is the current in amperes, and R is the resistance in ohms. In this case, given that the current (I) through a 38.1-ohm resistor is 55 mA (which is 0.055 amperes), the potential difference can be found by multiplying the current by the resistance, resulting in V = 0.055 A × 38.1 Ω.

Performing the calculation gives us the potential difference V = 2.0955 V. Therefore, the potential difference across the 38.1-ohm resistor is approximately 2.0955 volts when a current of 55 milliamps is flowing through it.

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