High School

You drive 5.10 mi at 35.5 mi/h and then another 9.5 mi at 57.5 mi/h. What is your average speed for the trip, in mi/h?

Answer :

The average speed for the entire trip is approximately 47.23 miles/hour.

To find the average speed for the entire trip in mph, you can use the formula:

average speed = total distance ÷ total time taken

We are given that:

Distance covered in the first part of the trip (d₁) = 5.10 miles

Speed in the first part of the trip (s₁) = 35.5 miles/hour

Distance covered in the second part of the trip (d₂) = 9.5 miles

Speed in the second part of the trip (s₂) = 57.5 miles/hour

Total distance covered (d) = d₁ + d₂ = 5.10 + 9.5 = 14.6 miles

Average speed = total distance ÷ total time taken

To find the total time taken, we need to divide each distance by its respective speed and then add up the times taken in both parts of the trip.

Time taken in first part of the trip = distance ÷ speed

= d₁/s₁

= 5.10/35.5 hours

Time taken in the second part of the trip = distance ÷ speed

= d₂/s₂

= 9.5/57.5 hours

total time taken = time taken in first part of the trip + time taken in the second part of the trip

= 5.10/35.5 + 9.5/57.5 hours

= 0.144 + 0.165 hours

= 0.309 hours

Now, we can calculate the average speed as:

average speed = total distance ÷ total time taken

= 14.6 miles ÷ 0.309 hours≈ 47.23 miles/hour

Therefore, the average speed for the entire trip is approximately 47.23 miles/hour.

To know more about average speed visit:

https://brainly.com/question/17277454

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