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You are helping with some repairs at home. You drop a hammer, and it hits the floor at a speed of 4 feet per second. If the acceleration due to gravity (\( g \)) is 32 feet/second\(^2\), how far above the ground (\( h \)) was the hammer when you dropped it? Use the formula: [tex] V = \sqrt{2gh} [/tex]

Answer :

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the given formula

[tex][/tex]

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