High School

Write an expression that is equivalent to [tex]\frac{2}{3}(4x + 9)[/tex].

A. [tex]\frac{8}{3}x + 6[/tex]
B. [tex]\frac{8}{3}x + 9[/tex]
C. [tex]\frac{2}{3}x + 6[/tex]
D. [tex]\frac{2}{3}x + 9[/tex]

Answer :

Answer:

it is A

Step-by-step explanation:
[tex]\frac{2}{3}(4x+9)=\frac{2}{3}(4x)+\frac{2}{3}(9)=\frac{8}{3}x+\frac{18}{3}=\boxed{\frac{8}{3}x+6}\\\\used\ distributive\ property:\ a(b+c)=ab+ac[/tex]

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