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Write a function to describe the following scenario:

A garden watering bucket has 3000 milliliters of water in it, but there is a hole that is leaking 18 milliliters every minute. How much water remains in the container after a certain number of minutes?

[tex]y = 3000 - 18x[/tex]

Answer :

We start by noting that the initial amount of water in the bucket is

[tex]$$3000 \text{ ml},$$[/tex]

and the leak causes the water to decrease by

[tex]$$18 \text{ ml per minute}.$$[/tex]

Let [tex]$x$[/tex] be the number of minutes that have elapsed. The decrease in water due to the leak after [tex]$x$[/tex] minutes is

[tex]$$18x \text{ ml}.$$[/tex]

Thus, the amount of water remaining in the bucket after [tex]$x$[/tex] minutes is given by subtracting the water lost from the initial amount:

[tex]$$ y = 3000 - 18x. $$[/tex]

For example, if we want to find the amount of water remaining after 15 minutes, substitute [tex]$x = 15$[/tex] into the equation:

[tex]$$
\begin{aligned}
y &= 3000 - 18(15) \\
&= 3000 - 270 \\
&= 2730.
\end{aligned}
$$[/tex]

So, after 15 minutes, there would be [tex]$2730$[/tex] milliliters of water remaining in the bucket.

To summarize:
- The function describing the remaining water is [tex]$$y = 3000 - 18x.$$[/tex]
- After 15 minutes, [tex]$$y = 2730 \text{ ml}.$$[/tex]

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