Answer :
Certainly! Let's solve the inequality step-by-step:
We are given the inequality:
[tex]\[ x + 8 < 12 \][/tex]
We want to find the largest integer value that [tex]\( x \)[/tex] could take.
Step 1: Subtract 8 from both sides of the inequality to isolate [tex]\( x \)[/tex]:
[tex]\[ x + 8 - 8 < 12 - 8 \][/tex]
This simplifies to:
[tex]\[ x < 4 \][/tex]
Step 2: Determine the largest integer [tex]\( x \)[/tex] that satisfies this inequality.
Since [tex]\( x \)[/tex] must be less than 4, the largest integer value that [tex]\( x \)[/tex] can take is 3.
Thus, the largest integer value for [tex]\( x \)[/tex] is 3.
We are given the inequality:
[tex]\[ x + 8 < 12 \][/tex]
We want to find the largest integer value that [tex]\( x \)[/tex] could take.
Step 1: Subtract 8 from both sides of the inequality to isolate [tex]\( x \)[/tex]:
[tex]\[ x + 8 - 8 < 12 - 8 \][/tex]
This simplifies to:
[tex]\[ x < 4 \][/tex]
Step 2: Determine the largest integer [tex]\( x \)[/tex] that satisfies this inequality.
Since [tex]\( x \)[/tex] must be less than 4, the largest integer value that [tex]\( x \)[/tex] can take is 3.
Thus, the largest integer value for [tex]\( x \)[/tex] is 3.
