High School

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------------------------------------------------ Which equation, when solved, results in a different value of [tex]$x$[/tex] than the other three?

A. [tex]8.3 = -0.6x + 11.3[/tex]
B. [tex]11.3 = 8.3 + 0.6x[/tex]
C. [tex]11.3 - 0.6x = 8.3[/tex]
D. [tex]8.3 - 0.6x = 11.3[/tex]

Answer :

We begin by solving each equation for [tex]\( x \)[/tex].

1. For the equation
[tex]$$
8.3 = -0.6x + 11.3,
$$[/tex]
subtract [tex]\( 11.3 \)[/tex] from both sides:
[tex]$$
8.3 - 11.3 = -0.6x.
$$[/tex]
This simplifies to:
[tex]$$
-3.0 = -0.6x.
$$[/tex]
Dividing both sides by [tex]\(-0.6\)[/tex] gives:
[tex]$$
x = \frac{-3.0}{-0.6} = 5.0.
$$[/tex]

2. For the equation
[tex]$$
11.3 = 8.3 + 0.6x,
$$[/tex]
subtract [tex]\( 8.3 \)[/tex] from both sides:
[tex]$$
11.3 - 8.3 = 0.6x.
$$[/tex]
This simplifies to:
[tex]$$
3.0 = 0.6x.
$$[/tex]
Dividing by [tex]\( 0.6 \)[/tex] yields:
[tex]$$
x = \frac{3.0}{0.6} = 5.0.
$$[/tex]

3. For the equation
[tex]$$
11.3 - 0.6x = 8.3,
$$[/tex]
subtract [tex]\( 8.3 \)[/tex] from both sides:
[tex]$$
11.3 - 8.3 = 0.6x.
$$[/tex]
This gives:
[tex]$$
3.0 = 0.6x.
$$[/tex]
Dividing both sides by [tex]\( 0.6 \)[/tex] results in:
[tex]$$
x = \frac{3.0}{0.6} = 5.0.
$$[/tex]

4. For the equation
[tex]$$
8.3 - 0.6x = 11.3,
$$[/tex]
subtract [tex]\( 8.3 \)[/tex] from both sides:
[tex]$$
-0.6x = 11.3 - 8.3.
$$[/tex]
This simplifies to:
[tex]$$
-0.6x = 3.0.
$$[/tex]
Dividing both sides by [tex]\(-0.6\)[/tex] gives:
[tex]$$
x = \frac{3.0}{-0.6} = -5.0.
$$[/tex]

The first three equations yield [tex]\( x = 5.0 \)[/tex] while the fourth equation gives [tex]\( x = -5.0 \)[/tex]. Therefore, the equation that results in a different value of [tex]\( x \)[/tex] is the fourth equation.