College

Which equation, when solved, results in a different value of [tex] x [/tex] than the other three?

A. [tex] 8.3 = -0.6x + 11.3 [/tex]

B. [tex] 11.3 = 8.3 + 0.6x [/tex]

C. [tex] 11.3 - 0.6x = 8.3 [/tex]

D. [tex] 8.3 - 0.6x = 11.3 [/tex]

Answer :

To find out which equation results in a different value for [tex]\( x \)[/tex] compared to the others, let's solve each equation for [tex]\( x \)[/tex].

1. Equation 1: [tex]\( 8.3 = -0.6x + 11.3 \)[/tex]

- Start by isolating [tex]\( x \)[/tex]:
- Subtract 11.3 from both sides:
[tex]\( 8.3 - 11.3 = -0.6x \)[/tex]
- Simplify:
[tex]\( -3 = -0.6x \)[/tex]
- Divide both sides by -0.6:
[tex]\( x = \frac{-3}{-0.6} = 5 \)[/tex]

2. Equation 2: [tex]\( 11.3 = 8.3 + 0.6x \)[/tex]

- Isolate [tex]\( x \)[/tex]:
- Subtract 8.3 from both sides:
[tex]\( 11.3 - 8.3 = 0.6x \)[/tex]
- Simplify:
[tex]\( 3 = 0.6x \)[/tex]
- Divide both sides by 0.6:
[tex]\( x = \frac{3}{0.6} = 5 \)[/tex]

3. Equation 3: [tex]\( 11.3 - 0.6x = 8.3 \)[/tex]

- Isolate [tex]\( x \)[/tex]:
- Subtract 8.3 from both sides:
[tex]\( 11.3 - 8.3 = 0.6x \)[/tex]
- Simplify:
[tex]\( 3 = 0.6x \)[/tex]
- Divide both sides by 0.6:
[tex]\( x = \frac{3}{0.6} = 5 \)[/tex]

4. Equation 4: [tex]\( 8.3 - 0.6x = 11.3 \)[/tex]

- Isolate [tex]\( x \)[/tex]:
- Subtract 8.3 from both sides:
[tex]\( -0.6x = 11.3 - 8.3 \)[/tex]
- Simplify:
[tex]\( -0.6x = 3 \)[/tex]
- Divide both sides by -0.6:
[tex]\( x = \frac{3}{-0.6} = -5 \)[/tex]

Upon solving these equations, we find that for Equations 1, 2, and 3, the value of [tex]\( x \)[/tex] is 5. However, for Equation 4, the value of [tex]\( x \)[/tex] is -5. Therefore, Equation 4 results in a different value of [tex]\( x \)[/tex] than the other three equations.