College

Which equation, when solved, results in a different value of [tex]$x$[/tex] than the other three?

A. [tex]8.3 = -0.6x + 11.3[/tex]
B. [tex]11.3 = 8.3 + 0.6x[/tex]
C. [tex]11.3 - 0.6x = 8.3[/tex]
D. [tex]8.3 - 0.6x = 11.3[/tex]

Answer :

Let's solve each of these equations step by step to see which one results in a different value of [tex]\( x \)[/tex].

1. Equation 1:
[tex]\( 8.3 = -0.6x + 11.3 \)[/tex]
- First, subtract 11.3 from both sides:

[tex]\[ 8.3 - 11.3 = -0.6x \][/tex]

[tex]\[-3.0 = -0.6x\][/tex]

- Next, divide both sides by -0.6 to solve for [tex]\( x \)[/tex]:

[tex]\[ x = \frac{-3.0}{-0.6} \][/tex]

[tex]\[ x = 5 \][/tex]

2. Equation 2:
[tex]\( 11.3 = 8.3 + 0.6x \)[/tex]
- First, subtract 8.3 from both sides:

[tex]\[ 11.3 - 8.3 = 0.6x \][/tex]

[tex]\[ 3.0 = 0.6x \][/tex]

- Then, divide both sides by 0.6 to solve for [tex]\( x \)[/tex]:

[tex]\[ x = \frac{3.0}{0.6} \][/tex]

[tex]\[ x = 5 \][/tex]

3. Equation 3:
[tex]\( 11.3 - 0.6x = 8.3 \)[/tex]
- First, subtract 8.3 from both sides:

[tex]\[ 11.3 - 8.3 = 0.6x \][/tex]

[tex]\[ 3.0 = 0.6x \][/tex]

- Divide both sides by 0.6 to solve for [tex]\( x \)[/tex]:

[tex]\[ x = \frac{3.0}{0.6} \][/tex]

[tex]\[ x = 5 \][/tex]

4. Equation 4:
[tex]\( 8.3 - 0.6x = 11.3 \)[/tex]
- First, subtract 8.3 from both sides:

[tex]\[ 8.3 - 8.3 - 0.6x = 11.3 - 8.3 \][/tex]

[tex]\[ -0.6x = 3.0 \][/tex]

- Now, divide both sides by -0.6 to solve for [tex]\( x \)[/tex]:

[tex]\[ x = \frac{3.0}{-0.6} \][/tex]

[tex]\[ x = -5 \][/tex]

By solving these equations separately, you can see that Equations 1, 2, and 3 all result in [tex]\( x = 5 \)[/tex]. However, Equation 4 results in [tex]\( x = -5 \)[/tex], which is different.

Therefore, the equation that results in a different value of [tex]\( x \)[/tex] than the others is:
[tex]\[ 8.3 - 0.6x = 11.3 \][/tex]