High School

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------------------------------------------------ Which equation, when solved, results in a different value of [tex]$x$[/tex] than the other three?

A. [tex]8.3 = -0.6 x + 11.3[/tex]

B. [tex]11.3 = 8.3 + 0.6 x[/tex]

C. [tex]11.3 - 0.6 x = 8.3[/tex]

D. [tex]8.3 - 0.6 x = 11.3[/tex]

Answer :

Let's analyze each of the equations and find out which one results in a different value for [tex]\( x \)[/tex].

1. Equation 1: [tex]\( 8.3 = -0.6 x + 11.3 \)[/tex]

To solve for [tex]\( x \)[/tex], subtract 11.3 from both sides:

[tex]\[
8.3 - 11.3 = -0.6 x
\][/tex]
[tex]\[
-3.0 = -0.6 x
\][/tex]

Divide both sides by -0.6:

[tex]\[
x = \frac{-3.0}{-0.6} = 5.0
\][/tex]

2. Equation 2: [tex]\( 11.3 = 8.3 + 0.6 x \)[/tex]

Subtract 8.3 from both sides:

[tex]\[
11.3 - 8.3 = 0.6 x
\][/tex]
[tex]\[
3.0 = 0.6 x
\][/tex]

Divide both sides by 0.6:

[tex]\[
x = \frac{3.0}{0.6} = 5.0
\][/tex]

3. Equation 3: [tex]\( 11.3 - 0.6 x = 8.3 \)[/tex]

Subtract 8.3 from both sides:

[tex]\[
11.3 - 8.3 = 0.6 x
\][/tex]
[tex]\[
3.0 = 0.6 x
\][/tex]

Solve for [tex]\( x \)[/tex] by dividing both sides by 0.6:

[tex]\[
x = \frac{3.0}{0.6} = 5.0
\][/tex]

4. Equation 4: [tex]\( 8.3 - 0.6 x = 11.3 \)[/tex]

Subtract 8.3 from both sides:

[tex]\[
-0.6 x = 11.3 - 8.3
\][/tex]
[tex]\[
-0.6 x = 3.0
\][/tex]

Divide both sides by -0.6:

[tex]\[
x = \frac{3.0}{-0.6} = -5.0
\][/tex]

As we can observe, the solutions for the first three equations result in [tex]\( x = 5.0 \)[/tex], while the fourth equation solves to [tex]\( x = -5.0 \)[/tex]. Therefore, the equation that results in a different value of [tex]\( x \)[/tex] is the fourth one:

[tex]\[
8.3 - 0.6 x = 11.3
\][/tex]